3x^2-200x-200=0

Solution for 3x^2-200x-200=0 equation:

3x^2-200x-200=0

a = 3; b = -200; c = -200;
Δ = b2-4ac
Δ = -2002-4·3·(-200)
Δ = 42400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{42400}=\sqrt{400*106}=\sqrt{400}*\sqrt{106}=20\sqrt{106}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-20\sqrt{106}}{2*3}=\frac{200-20\sqrt{106}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+20\sqrt{106}}{2*3}=\frac{200+20\sqrt{106}}{6}
$